(x^3+7x^2-36)/(x+6)

Solution for (x^3+7x^2-36)/(x+6) equation:

D( x )

x+6 = 0

x+6 = 0

x+6 = 0

x+6 = 0 // - 6

x = -6

x in (-oo:-6) U (-6:+oo)

(x^3+7*x^2-36)/(x+6) = 0

x^3+7*x^2-36 = 0

x^3+7*x^2-36 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 9, -9, 12, -12, 18, -18, 36, -36 }

1

x = 1

x^3+7*x^2-36 = -28

1

-1

x = -1

x^3+7*x^2-36 = -30

-1

2

x = 2

x^3+7*x^2-36 = 0

2

x-2

x^2+9*x+18

x^3+7*x^2-36

x-2

2*x^2-x^3

9*x^2-36

18*x-9*x^2

18*x-36

36-18*x

0

x^2+9*x+18 = 0

DELTA = 9^2-(1*4*18)

DELTA = 9

DELTA > 0

x = (9^(1/2)-9)/(1*2) or x = (-9^(1/2)-9)/(1*2)

x = -3 or x = -6

x in { -6, -3, 2} 

(x+6)*(x+3)*(x-2) = 0

(x+3)*(x-2) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -3, 2 }